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Can you help me with this chem question f

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Hello can you help me with this chem question f

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Thank you for your question. I am gladly here to help.



e) 5.48 x 10^23

f) C6H6O

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Customer: replied 6 months ago.
Can you show me the working out please and explain how you did it

e) The molecular mass of K2O is

K =2 x 39.10 = 78.20

O = 1 x 16 = 16

Total = 94.20

Moles of K2O = 85.7 / 94.20 = 0.909766

Number of atoms = 6.022 x 10^23 x 0.909766 = 5.48 x 10^23

Customer: replied 6 months ago.
Okay understood what about f?
Customer: replied 6 months ago.


Total Mass of C = 76.6 /12.01 = 6.38

Total Mass of H = 6.4 / 1.01 = 6.3366

Total Mass of O = 17 / 16 = 1.0625

Divide by the lowest number to find the ratio.

C = 6.38/ 1.0625 = 6

H = 6.3366 / 1.0625 = 6

O = 1.0625 / 1.0625 = 1

Thus, C6H6O

Customer: replied 6 months ago.
Thank youu so much
Customer: replied 6 months ago.
I understood everything

You are most welcome!

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