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Ashok Kumar
Ashok Kumar, Electrical Engineer
Category: Math Homework
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Experience:  Master's Degree
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The equation of a curve is y=(x+1)(x-5) find the area of the

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The equation of a curve is y=(x+1)(x-5) find the area of the triangle formed by the normal at (6,7) and the coordinate axes. Could you show me a work through of this example.

When due?

Customer: replied 1 year ago.
Would be great if I could get that example worked this evening.
Customer: replied 1 year ago.
The quicker the better in fact

Ok

y = (x+1)(x-5)

=x^2-4x-5

slope o& tangent = 2x-4

At x =6, tangent slope =6*3-4=8

Normal slope =-1/8

Hence, normal eqn.

y-7=(-1/8)(x-6)

or, x+8y=62

X-intercept: (62,0)

y-intercept:(0,62/8)

hence, area of the triangle formed by normal and co-ordinate axes

=(1/2)*62*(62/8)=240.25. Ans.

fig

pl rate the answer 5 stars if no clarification is needed.

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Customer: replied 1 year ago.
Thank you so much - that helped a great deal - if you have time a little more explanation of the steps would be helpful.