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Sandhya_sharma
Sandhya_sharma, Master's Degree
Category: Pre-Calculus
Satisfied Customers: 10699
Experience:  I hold M.Sc and M.Phil degrees in math and have several years of teaching experience.
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T(s(x))) t(x) = 2x-6 s(x) = 1/2x+3 So t(1/2x+3) 2(1/2x+3)-6

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t(s(x)))t(x) = 2x-6
s(x) = 1/2x+3So t(1/2x+3)2(1/2x+3)-6= 1x+6-6= 1x?

t(s(x))

= t((1/2)x + 3)

replace x by (1/2)x + 3 in definition of t(x)

= 2((1/2)x + 3) - 6

open parenthesis

= x + 6 - 6

= x

I hope it will help you.

Thanks

Sandhya_sharma and other Pre-Calculus Specialists are ready to help you
Customer: replied 6 days ago.
Well suppose 1x and x are the same thing so looks like I'm somewhat understanding it now, haha. Thank you.

yes, 1x and x are the same..

If you get 1x then just write it x..

I hope it will help.

Thanks

sorry, I missed your request.

Please request me if you still need help.

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